40. Solve Lim [1/x log(1+x)/x²]
Equazioni esponenziali e logaritmiche: \frac{{ \log{{\left({x}-{1}\right)}}}}{ \log{{\left({x}^{3}-{8}{x}+{5}\right)}}}=\frac{1}{{3}}
Evaluate: ∫ x log (1 + x) dx - Sarthaks eConnect | Largest Online Education Community
Integrate : `int(log(1-x))/(x^(2))dx` - YouTube
Ex 6.2, 7 - Show that y = log (1 + x) - 2x/(2 + x) is an increasing fn
7. Solve for x : log(x 1)+log(x+1) = log of 1 to the base 2
Obtain the Maclaurin's expansion of the function log(1+x) up to 4th degree terms – Yawin
What is the integration of log 1/x? - Quora
If y = x^{3} log left ( dfrac{1}x{} right ), the prove that xdfrac{d^{2}y}{dx^{2}} - 2dfrac{dy}{dx} + 3x^{2} = 0.
How to recognise expansion of log(1+x)-log(1-x) - Maths - - 16191679 | Meritnation.com
Answered: x² x3 log(1 + x) = x – - 2 3 4 for -1 <… | bartleby
y = log(1+x) – GeoGebra
If f (x) = log ( 1 - x ),0 < x < 1 , then show that f ( 11 + x ) = f ( 1 - x ) - f ( - x ) .
Derivative of 1/logx | 1 by log x Derivative - iMath
Matematica Generale - Derivate, integrali, funzione logaritmica
Expansion Of log(1-x) | Maclaurin series - YouTube
log(1+x)の0でのテイラー展開(マクローリン展開) | 数学の景色
![Expand ( [ log ( 1 + x ) ] ^ { 2 } ) is ascending prower of ( x ) , concilnunto fourth power of ( x ) ."](https://toppr-doubts-media.s3.amazonaws.com/images/3816188/b0a35928-0b65-47e1-9aab-ad99487c5acc.jpg "Expand ( [ log ( 1 + x ) ] ^ { 2 } ) is ascending prower of ( x ) , concilnunto fourth power of ( x ) .\"")
Expand ( [ log ( 1 + x ) ] ^ { 2 } ) is ascending prower of ( x ) , concilnunto fourth power of ( x ) ."
Find the limit as approaches 0 (log(1+x)/x) - YouTube
Expand log (1 + e^x) in ascending powers of x up to the term containing x^4. - Sarthaks eConnect | Largest Online Education Community
